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What If Earth Rotated Twice as Fast?

What does a shorter day do to ground speed and apparent weight?

A 24-hour day is a habit, not a law. Earth's sidereal spin is a little under that, and the solar day is the 86 400 seconds we count. Multiply the spin and two things move at once: the Sun crosses the sky faster, and the ground at the equator has to travel farther per second to complete the turn. There is also a quieter change. Rotation already reduces apparent weight a little through a centrifugal term, ω² R cos²(latitude). Faster spin, larger term, slightly lighter footsteps at low latitudes. At four times today's ω that term is no longer a rounding error. Over long times the planet would also grow more oblate. This page does the first-order numbers and leaves the new figure of the Earth to geology.

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Results update as you move the controls.

2×

2 is a 12-hour-ish day.

51.5°

Your result

11.97 hours

new length of a sidereal day

today 23.934 hours sidereal

Ground speed at this latitude
579 m/s

2,085 km/h

Centrifugal term
0.053 m/s²
Apparent g
9.754 m/s²
Apparent g today, same latitude
9.794 m/s²
Change in apparent weight
-0.4%

What does that mean?

At 2× today's spin, a sidereal day is 11.97 hours. At 51.5°N the ground moves east at 579 m/s (2,085 km/h), versus 290 m/s now. Apparent g is 9.754 m/s² here, down from 9.794 m/s² today, because the centrifugal term rose to 0.053 m/s². That is a lighter footstep, not weightlessness. A fatter equator would take geological time.

At a glance

  • Day now (sidereal hours)23.93 h
  • Day in this run11.97 h

Compare

Equator speed now465 m/s
Equator speed in this run930 m/s
51.5°N579 m/s

Compare scenarios

The day is just 2π / ω

Double ω and the sidereal day halves. Clocks that track the Sun would show something close to a 12-hour solar day at 2×. Biology that entrains to light would be asked to fit two cycles where it now fits one. This experiment does not redesign sleep. It prints the new length of day and the new ground speed at your latitude, using the same cosine law as the stopped-spinning page, only in the other direction.

A little less apparent g

Effective gravity in the rotating frame is g minus the local centrifugal acceleration. At the equator today that subtraction is about 3.4 cm/s², a third of a percent. It grows as the square of the spin. At 2× it is four times today's centrifugal term; at 4× it is sixteen times. Poles do not get the discount: cos(90°) is zero. Nobody is flung into space at 2×. At much higher multiples the equatorial effective g could approach zero, which is a different, more dramatic slider than this one allows.

Oblateness is a long job

Earth is already an ellipsoid because it spins: WGS 84 is not a sphere. Spin it faster and, given time, rock and ocean would adjust toward a fatter equator. That is hydrostatic equilibrium on a geological clock, not an afternoon. Weather would also meet a stronger Coriolis parameter. This model will mention those and will not run a GCM or a viscoelastic Earth. If you want zero spin instead of more spin, the stopped-spinning experiment is the counterpart.

How we calculated this

Present ω is 2π / sidereal day. New ω is that times the spin multiple. Day length is 2π / ω_new in hours. Ground speed is ω_new × R_eq × cos(latitude). Apparent g is gn minus ω² R cos²(lat), never printed as negative without comment (the slider stops at 4×, where equatorial g_eff is still positive). Oblateness and Coriolis are qualitative. WGS 84 equatorial radius and NIST gn.

Go further

A curated rabbit hole from this question. Each link is a real experiment, not a random suggestion.

  1. 01 · WorldWhat If Earth Stopped Spinning?
  2. 02 · ScienceWhat If You Fell Through the Earth?
  3. 03 · WorldWhat If Earth Was Twice as Large?
  4. 04 · ScienceWhat If Gravity Stopped?

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